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Fit Latina babe Kitana Montana gets a real good workout on a real big cock

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1 year ago
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    1 year ago
    --1DECLARE v_emp_id employees.employee_id%TYPE; v_dept_name departments.department_name%TYPE;BEGIN v_emp_id := &v_emp_id; SELECT department_name INTO v_dept_name FROM departments WHERE department_id = (SELECT department_id FROM employees WHERE employee_id = v_emp_id); DBMS_OUTPUT.PUT_LINE('Le département de l''employé est : ' v_dept_name);END;/--2DECLARE v_dept_id departments.department_id%TYPE; v_count NUMBER;BEGIN v_dept_id := &v_dept_id; SELECT
    1 year ago
    --exercice 1-- 1select department_namefrom departmentsminus select department_namefrom departments d join employees e ond.department_id=e.department_id;--2SELECT department_name, COUNT(employee_id) AS employee_countFROM employeesRIGHT JOIN departments ON employees.department_id = departments.department_idGROUP BY department_name;--3SELECT department_nameFROM departmentsJOIN employees ON departments.department_id = employees.department_idGROUP BY department_nameHAVING COUNT(employee_id) 3;--4SE

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